郭先强和陈漱文的合作研究
- 导言
- The Prouhet-Tarry-Escott problem can
be stated as:
- Given a positive integer n, find
two sets of integer solutions { a1, a2,
... , am } and { b1, b2,
... , bm } such that the integers in each set
have the same sum, the same sum of squares, etc., up to and
including the same sum of nth powers, i.e., we
are to find solutions in integers of the system of equations
- a1k +
a2k + ... + amk
= b1k + b2k
+ ... + bmk ( k
= 1, 2, ..., n )
- Solutions of this system will be denoted
here by the notation
- [ a1 , a2
, ... , am ] = [ b1
, b2 , ... , bm ] ( k
= 1, 2, ..., n )
- A good online reference by Peter
Borwein and Colin Ingalls: The
Prouhet-Tarry-Escott Problem Revisited. [44]
- 介绍
- Guo Xianqiang
studied the k < 0 cases of the Equal sums of
like powers system first. He gave some numerial examples such as the
following solution for ( k = 0, -1, -2, -3, -4 ) before
march of 2001:
- [684, 855, 1140, 2160, 4104, 4560, 20520 ]
= [ 720, 760, 1368, 2052, 2565, 10260, 13680 ]
- In Guo Xianqiang's site on Equal
sums of like powers ( in Chinese), he ask such an interesting
question :
- If k1< 0 and kn
> 0 , is there solution in positive integers?
- Guo Xianqiang guessed the answer is NO.
However, Chen Shuwen solved ( k = -1, 1 ) in
May of 2001.
- In April of 2001, Chen Shuwen noticed that, if
all the k<=0, ( k = k1, k2
, ... , kn ), solutions can be easily obtained by
simply transforming from a corresponding known type:
- [ a1 , a2
, ... , am ] = [ b1
,b2 , ... , bm ]
( k = k1, k2 ,
... , kn )
- <=> [ C/a1
, C/a2 , ... , C/am ]
= [ C/b1 ,C/b2 , ... ,
C/bm ] ( k = -k1,
-k2 , ... , -k
- 资料介绍
- The Equal Products and Equal Sums of Like
Powers is the system of the form
- a1a2
... am = b1 b2 ... bm
- a1k + a2k
+ ... + amk = b1k +
b2k + ... + bmk
( k = k2 , k3 ,
... , kn )
- This system has been studied for a long time
when k <= 3.[13]
[5] [17]
[6] [59]
- In March of 2001, for the first time, Guo
Xianqiang and Chen Shuwen found that the equal products equation
can be regarded as the k = 0 case of the Equal Sums of Like
Powers system.
- In these pages, we will denote the Equal
Products and Equal Sums of Like Powers system as:
- [ a1 , a2
, ... , am ] = [ b1 ,b2
, ... , bm ]
( k = 0, k2 , k3 ,
... , kn</